20y^2+59y-3=

Solution for 20y^2+59y-3= equation:

Simplifying
20y2 + 59y + -3 = 0

Reorder the terms:
-3 + 59y + 20y2 = 0

Solving
-3 + 59y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-3 + -1y)(1 + -20y) = 0

Subproblem 1
Set the factor '(-3 + -1y)' equal to zero and attempt to solve:

Simplifying
-3 + -1y = 0

Solving
-3 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1y = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1y = 0 + 3
-1y = 0 + 3

Combine like terms: 0 + 3 = 3
-1y = 3

Divide each side by '-1'.
y = -3

Simplifying
y = -3
Subproblem 2
Set the factor '(1 + -20y)' equal to zero and attempt to solve:

Simplifying
1 + -20y = 0

Solving
1 + -20y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -20y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -20y = 0 + -1
-20y = 0 + -1

Combine like terms: 0 + -1 = -1
-20y = -1

Divide each side by '-20'.
y = 0.05

Simplifying
y = 0.05
Solution
y = {-3, 0.05}